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Suppose we have the polynomial `P(x) = x³ + 2x² + 3x + 4` and we want to evaluate it at `x = 2`. The first step is to rewrite the polynomial using **Horner's Scheme**: `P(x) = 4 + x(3 + x(2 + x(1)))`. Then, substitute `x = 2`: `P(2) = 4 + 2(3 + 2(2 + 2(1)))`. Now, we do the calculations from the inside out: `P(2) = 4 + 2(3 + 2(4)) = 4 + 2(3 + 8) = 4 + 2(11) = 4 + 22 = 26`. So, the value of the polynomial at `x = 2` is 26. This is straightforward and illustrates the simplicity of the approach. Always double-check your calculations to ensure accuracy.
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